Finished the go fish program.

assignmentOne/go_fish.cpp

@@ -265,7 +265,7 @@ int humanTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &cardDec
         human.push_back(cardDeck.back());
         cardDeck.pop_back();
         cout << "Opponent does not have " << inputChar << ". You go fish." << endl;
-        cout << "New Card: " << human[human.size() - 1].getFullCard() << endl;
+        cout << "New Card: " << human[human.size()-1].getFullCard() << endl; // also try human.end()???
     }
     // check to see if sets exist in the vector, aka is there four of a value.
         // if there is four of a value, increase the number of sets to return, remove the cards from hand.
@@ -324,6 +324,79 @@ int computerTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &card
     Handles the computer’s turn and it should do the same actions as the human but for the
     computer. The function should return the number of set that is collected during its turn.
     */
+    int numSets = 0;
+    int maxCountCard = 0;
+    char inputChar = computer[0].getCardRawValue();
+    bool foundCard = false;
+    bool foundSet = false;
+    cout << "Opponent's turn. They asked for: " << inputChar << endl;
+    // ask for card rank/number/value
+    int humanHandSize = human.size();
+    // if card is in opposite hand, remove from and give to the other. (loop through human hand looking for card)
+    for(int checkHandIterator = 0; checkHandIterator < humanHandSize; checkHandIterator++)
+    {
+        // checking if value of card is equal to any of the other ones.
+        if(human[checkHandIterator].getCardRawValue() == inputChar)
+        {
+            // copy the card into the human's hand.
+            human.push_back(human[checkHandIterator]);
+            // set the card find to true.
+            foundCard = true;
+            cout << "You have " << human[checkHandIterator].getFullCard();
+            cout << ". They collect all " << inputChar << "s." << endl;
+        }
+    }
+    // remove the cards that had been drawn from the other hand (use remove/remove if and erase with the vector iterators)
+    if(foundCard)
+    {
+        // remove cards if found
+        human.erase(remove_if(human.begin(), human.end(), 
+                                 [&](Card &remCard){return remCard.getCardValue() == inputChar;}), human.end());
+    }
+    // if not, draw a card from the top of the deck.
+    else
+    {
+        // draw a card if not found.
+        computer.push_back(cardDeck.back());
+        cardDeck.pop_back();
+    }
+    // check to see if sets exist in the vector, aka is there four of a value.
+        // if there is four of a value, increase the number of sets to return, remove the cards from hand.
+    // NOTE TO PROGRAMMER: https://stackoverflow.com/questions/39906504/how-to-count-duplicates-in-a-vector-c
+    sort(computer.begin(), computer.end());
+    // had to use the stupid auto keyword here to make the damn iterator move... kept getting bad casting types.
+    for (auto cardIterator = computer.cbegin(); cardIterator != computer.cend();)
+    {
+        maxCountCard = count(cardIterator, computer.cend(), *cardIterator);
+        if(maxCountCard == 4)
+        {
+            // this is where I make sure that there is a set here before removing it, 
+            // and set return value here.
+            numSets = numSets + 1;
+            foundSet = true;
+        }
+        // skip around until duplicates are found, using a trick that I researched.
+        for(auto lastChar = *cardIterator; *++cardIterator == lastChar;)
+        {
+            // this above for loop essentially keeps the iterator moving
+            // intentional empty block, since iterator must keep moving, but I don't need to do anything.
+        }
+    }
+    if(foundSet)
+    {
+        // if a valid set is found, remove all four cards from the computer's hand.
+        computer.erase(remove_if(computer.begin(), computer.end(), 
+                                 [&](Card &remCard){return remCard.getCardValue() == inputChar;}), computer.end());
+    }
+    // display hand to computer.
+    int handSize = human.size();
+    cout << "Your Hand: " << endl;
+    cout << "| ";
+    for(int handDisplayIterator = 0; handDisplayIterator < handSize; handDisplayIterator++)
+    {
+        cout << human[handDisplayIterator].getFullCard() << " | ";
+    }
+    cout << endl;
     // return the number of sets
-    return 0;
+    return numSets;
 }