Get the Go Fish human function almost completed, computer turn still needs work.

This commit is contained in:
Charles Descamps 2024-09-12 14:21:00 -07:00
parent b34d34a63d
commit ef2702e3a5
3 changed files with 80 additions and 8 deletions

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@ -90,6 +90,11 @@ class Card
//
return cardNumericalValue;
}
char getCardRawValue()
{
//
return cardValue;
}
char getCardSuit()
{
//
@ -99,6 +104,21 @@ class Card
{
return fullCard;
}
friend bool operator==(const Card &cardOne, const Card &cardTwo)
{
// compare cardOne's value to cardTwo's value.
// THIS WILL ONLY CHECK NUMERICAL VALUE
// If I was doing this for a REAL card game, I would add an
// && (cardOne.cardSuit == cardTwo.cardSuit)
// to make sure that the suit AND value are the same.
return (cardOne.cardNumericalValue == cardTwo.cardNumericalValue);
}
friend bool operator<(const Card &cardOne, const Card &cardTwo)
{
// compare cardOne's value to cardTwo's value with less than function.
// THIS WILL ONLY CHECK NUMERICAL VALUE
return (cardOne.cardNumericalValue < cardTwo.cardNumericalValue);
}
private:
char cardValue;
char cardSuit;
@ -107,8 +127,8 @@ class Card
};
// function prototypes
int humanTurn(vector<Card> &human, vector<Card> &computer);
int computerTurn(vector<Card> &human, vector<Card> &computer);
int humanTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &cardDeck);
int computerTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &cardDeck);
// main program
int main(int argc, char **argv)
@ -153,12 +173,22 @@ int main(int argc, char **argv)
computerHand.push_back(deck.back());
deck.pop_back();
}
// tell the user the game has started.
cout << "Game Start." << endl;
// output the human's hand to the screen
cout << "Here is your starting hand:" << endl << "| ";
int handSize = humanHand.size();
for(int handDisplayIterator = 0; handDisplayIterator < handSize; handDisplayIterator++)
{
cout << humanHand[handDisplayIterator].getFullCard() << " | ";
}
cout << endl;
// main gameplay loop (while?)
while(currentNumSets != 13)
{
// switch back and forth between human and computer.
currentNumSets = currentNumSets + humanTurn(humanHand, computerHand);
currentNumSets = currentNumSets + computerTurn(humanHand, computerHand);
currentNumSets = currentNumSets + humanTurn(humanHand, computerHand, deck);
currentNumSets = currentNumSets + computerTurn(humanHand, computerHand, deck);
}
// return 0
return 0;
@ -185,7 +215,7 @@ Device Input/Device: ???
Device Output/Monitor: ???
Dependencies: ???
*/
int humanTurn(vector<Card> &human, vector<Card> &computer)
int humanTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &cardDeck)
{
/*
Handles the human’s turn. It will prompt the player to ask for a card rank/number and
@ -194,11 +224,53 @@ int humanTurn(vector<Card> &human, vector<Card> &computer)
card. The function should return the number of sets collected during the turn
*/
int numSets = 0;
int maxCountCard = 0;
char inputChar;
bool foundCard = false;
// ask for card rank/number/value
// if card is in hand,
cout << "Your turn. Ask for a card (2-9, J/Q/K/A): " << endl;
cin.ignore();
cout << ">";
cin >> inputChar;
Card valueOnlyCard(inputChar, 'X');
// if card is in opposite hand, remove from and give to the other. (loop through computer hand looking for card)
for(int checkHandIterator = 0; checkHandIterator < computer.size(); checkHandIterator++)
{
// checking if value of card is equal to any of the other ones.
if(computer[checkHandIterator].getCardRawValue() == inputChar)
{
// copy the card into the human's hand.
human.push_back(computer[checkHandIterator]);
// set the card find to true.
foundCard = true;
}
}
// remove the cards that had been drawn from the other hand (use remove/remove if and erase with the vector iterators)
// NOTE: https://stackoverflow.com/questions/72179264/classes-remove-a-specific-object-from-a-vector-of-objects
if(foundCard)
{
// remove cards if found
computer.erase(remove_if(computer.begin(), computer.end(), [&](Card &remCard){return remCard.getCardValue() == inputChar;}), computer.end());
}
// if not, draw a card from the top of the deck.
else
{
// draw a card if not found.
human.push_back(cardDeck.back());
cardDeck.pop_back();
}
// check to see if sets exist in the vector, aka is there four of a value.
// if there is four of a value, increase the number of sets to return, remove the cards from hand.
// NOTE: https://stackoverflow.com/questions/39906504/how-to-count-duplicates-in-a-vector-c
for (int setCounter = 0; setCounter < human.size(); setCounter++)
{
/* code */
}
// return the number of sets
return 0;
return numSets;
}
/*
@ -211,7 +283,7 @@ Device Input/Device: ???
Device Output/Monitor: ???
Dependencies: ???
*/
int computerTurn(vector<Card> &human, vector<Card> &computer)
int computerTurn(vector<Card> &human, vector<Card> &computer, vector<Card> &cardDeck)
{
/*
Handles the computer’s turn and it should do the same actions as the human but for the

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