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Remove the IPYNB Checkpoints, Did Week 5 HW

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-- IPYNB Checkpoints
++ Git Ignore File for IPYNB Checkpoints
+- Week 5 Homework Files
This commit is contained in:
Charles Descamps 2022-09-28 21:30:48 -07:00
parent 4fc499169b
commit 140ffc6523
7 changed files with 219 additions and 60 deletions
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1
.gitignore vendored Normal file
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@ -0,0 +1 @@
.ipynb_checkpoints

40
Week-5/01_basic_names.ipynb
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@ -20,11 +20,22 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 7, "execution_count": 4,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"2.7182820533299275"
]
},
"execution_count": 4,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"roughly_e = ...\n", "roughly_e = (1 + (1/99999999999))**99999999999\n",
"roughly_e" "roughly_e"
] ]
}, },
@ -39,19 +50,30 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 2, "execution_count": 6,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"2.7182820533299275"
]
},
"execution_count": 6,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"n = ...\n", "n = 99999999999\n",
"also_roughly_e = ...\n", "also_roughly_e = (1+(1/n))**n\n",
"also_roughly_e" "also_roughly_e"
] ]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -65,7 +87,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.8.3" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,

20
Week-5/02_confusing_names.ipynb
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@ -40,20 +40,20 @@
}, },
"outputs": [], "outputs": [],
"source": [ "source": [
"a = 1410\n", "sun_density = 1410\n",
"b = 1.989 * 10**30\n", "sun_weight = 1.989 * 10**30\n",
"c = 3\n", "depth = 3\n",
"d = b / a\n", "sun_volume = sun_weight / sun_density\n",
"e = 3.14159\n", "pi = 3.14159\n",
"f = (d * 3/(4*e))**(1/3)\n", "sun_radius = (sun_volume * 3/(4*pi))**(1/3)\n",
"g = 4 * e * f**2\n", "sun_surface_area = 4 * pi * sun_radius**2\n",
"h = c * g" "required_beer_volume = depth * sun_surface_area"
] ]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -67,7 +67,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.7.1" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,

8
Week-5/03_naming_errors.ipynb
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@ -44,20 +44,20 @@
"outputs": [], "outputs": [],
"source": [ "source": [
"two = 2\n", "two = 2\n",
"four = two plus two" "four = two + two"
] ]
}, },
{ {
"cell_type": "markdown", "cell_type": "markdown",
"metadata": {}, "metadata": {},
"source": [ "source": [
"*Write your answer here, replacing this text.*" "Python didn't recognize the value called 'plus' and was probably confused about it being there, and since 'plus' is a mathmatical operation, I replaced 'plus' with '+' which when ran, gave no errors."
] ]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -71,7 +71,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.7.1" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,

91
Week-5/04_basic_arithmetic.ipynb
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@ -21,11 +21,22 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 1, "execution_count": 7,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"0.9999961853027344"
]
},
"execution_count": 7,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"..." "1 - (2**2 / 2**20)"
] ]
}, },
{ {
@ -39,21 +50,35 @@
"cell_type": "code", "cell_type": "code",
"execution_count": 9, "execution_count": 9,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"29.0"
]
},
"execution_count": 9,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"1 - 2 ** 3 / 4 + 5 * 6" "1 - 2 ** 3 / 4 + 5 * 6"
] ]
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": null, "execution_count": 8,
"metadata": { "metadata": {},
"collapsed": true
},
"outputs": [], "outputs": [],
"source": [ "source": [
"# Your prediction here:\n", "# Your prediction here: 29\n",
"..." "# Order of Operations: (L-R)\n",
"# 2 ** 3 = 8\n",
"# 8 / 4 = 2\n",
"# 5 * 6 = 30\n",
"# 1 - 2 = -1\n",
"# -1 + 30 = 29"
] ]
}, },
{ {
@ -67,7 +92,18 @@
"cell_type": "code", "cell_type": "code",
"execution_count": 10, "execution_count": 10,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"-1805811300.4191697"
]
},
"execution_count": 10,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"1 - 2 ** (3 / 4 + 5 * 6)" "1 - 2 ** (3 / 4 + 5 * 6)"
] ]
@ -76,7 +112,9 @@
"cell_type": "markdown", "cell_type": "markdown",
"metadata": {}, "metadata": {},
"source": [ "source": [
"*Write your answer here, replacing this text.*" "Prediction: The Value will be smaller, since everything in the parentheses will be done first, then that value will be the exponent for 2, aka 2 ^ value_in_parentheses, and then one will be added to that value(or subtracted depending on how you look at it), and will be shown.\n",
"\n",
"After cell execution: Right, and that is a rather large negative number."
] ]
}, },
{ {
@ -94,17 +132,36 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 8, "execution_count": 25,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"2.7182216960543433"
]
},
"execution_count": 25,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"..." "n = 1000000000000\n",
"(1-(1/n))**-n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"When you enter in 10000 for n, you get the 'rough' 2.718, and by adding more zeros, you get a value more precise. However, after adding more than 12 zeros, that number seems to make the rounding happen in a way that the value is no longer 2.718, but 2.719 and increasing the more zeros added..."
] ]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -118,7 +175,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.8.3" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,

45
Week-5/05_maxmin.ipynb
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@ -24,7 +24,8 @@
}, },
"outputs": [], "outputs": [],
"source": [ "source": [
"a + b + c - max(a, b, c) + min(a, b, c)" "a + b + c - (max(a, b, c) + min(a, b, c))\n",
"# Originally: a + b + c - max(a, b, c) + min(a, b, c)"
] ]
}, },
{ {
@ -38,15 +39,47 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": null, "execution_count": 6,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
"source": [] {
"data": {
"text/plain": [
"888"
]
},
"execution_count": 6,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"# Testing the interesting function: a + b + c - max(a, b, c) + min(a, b, c)\n",
"\n",
"# Using the test input vals a = 4, b = 2, c = 7\n",
"\n",
"##a = 4\n",
"##b = 2\n",
"##c = 7\n",
"\n",
"a = 999\n",
"b = 345\n",
"c = 888\n",
"\n",
"a + b + c - (max(a, b, c) + min(a, b, c))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Code was not correct, would return a value that is not the middle one. By adding parentheses before the call of max and after the call of min, you can return a middle value of three variables every single time."
]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -60,7 +93,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.8.3" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,

74
Week-5/06_rounding.ipynb
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@ -23,11 +23,23 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 3, "execution_count": 1,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"1.0"
]
},
"execution_count": 1,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"rounded = ...\n", "# Round can take two parameters, the first is the number to round, while the second is the decimal places in which to round to.\n",
"rounded = round(1.23456789, 0)\n",
"rounded" "rounded"
] ]
}, },
@ -42,11 +54,23 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 5, "execution_count": 2,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"1.235"
]
},
"execution_count": 2,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"less_rounded = ...\n", "# Using round, with the second parameter as three, you get three decimal point precision.\n",
"less_rounded = round(1.23456789, 3)\n",
"less_rounded" "less_rounded"
] ]
}, },
@ -67,11 +91,22 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 7, "execution_count": 3,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"71.0"
]
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"sum_of_rounded_amounts = ...\n", "sum_of_rounded_amounts = round(32.25, 0) + round(15.00, 0) + round(24.45, 0)\n",
"sum_of_rounded_amounts" "sum_of_rounded_amounts"
] ]
}, },
@ -84,18 +119,29 @@
}, },
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 9, "execution_count": 4,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [
{
"data": {
"text/plain": [
"72.0"
]
},
"execution_count": 4,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [ "source": [
"rounded_sum = ...\n", "rounded_sum = round((32.25 + 15.00 + 24.45), 0)\n",
"rounded_sum" "rounded_sum"
] ]
} }
], ],
"metadata": { "metadata": {
"kernelspec": { "kernelspec": {
"display_name": "Python 3", "display_name": "Python 3 (ipykernel)",
"language": "python", "language": "python",
"name": "python3" "name": "python3"
}, },
@ -109,7 +155,7 @@
"name": "python", "name": "python",
"nbconvert_exporter": "python", "nbconvert_exporter": "python",
"pygments_lexer": "ipython3", "pygments_lexer": "ipython3",
"version": "3.8.3" "version": "3.9.12"
} }
}, },
"nbformat": 4, "nbformat": 4,