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   "source": [
    "## The Middle"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Suppose that Yulin, another INF110 student, is tasked with writing code to find the middle of three distinct numbers named `a`, `b`, and `c`. (By “middle” we mean the value that is neither the maximum nor the minimum.) For example, given the values 4, 2, and 7, the code should give back 4.\n",
    "\n",
    "Yulin has a moment of inspired thought and rapidly types the following into her Jupyter notebook:"
   ]
  },
  {
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   "execution_count": null,
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   "source": [
    "a + b + c - (max(a, b, c) + min(a, b, c))\n",
    "# Originally: a + b + c - max(a, b, c) + min(a, b, c)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Is her code correct?  Why or why not?  If not, make a *simple* change to the cell above to fix it.\n",
    "\n",
    "*Hint:* Running the cell will produce an error because we haven't defined `a`, `b`, and `c`, but you're free to make any changes you want to test your ideas.  (When you submit, just indicate which cell is your final answer.)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "888"
      ]
     },
     "execution_count": 6,
     "metadata": {},
     "output_type": "execute_result"
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   "source": [
    "# Testing the interesting function: a + b + c - max(a, b, c) + min(a, b, c)\n",
    "\n",
    "# Using the test input vals a = 4, b = 2, c = 7\n",
    "\n",
    "##a = 4\n",
    "##b = 2\n",
    "##c = 7\n",
    "\n",
    "a = 999\n",
    "b = 345\n",
    "c = 888\n",
    "\n",
    "a + b + c - (max(a, b, c) + min(a, b, c))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Code was not correct, would return a value that is not the middle one. By adding parentheses before the call of max and after the call of min, you can return a middle value of three variables every single time."
   ]
  }
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